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142111413133 is a prime number
BaseRepresentation
bin1000010001011010000…
…0000001001110001101
3111120210222200210001121
42010112200001032031
54312021010210013
6145141324440541
713160440036504
oct2042640011615
9446728623047
10142111413133
11552a6208078
12236609a9151
131052a147991
146c41c0983b
153a6b29058d
hex211680138d

142111413133 has 2 divisors, whose sum is σ = 142111413134. Its totient is φ = 142111413132.

The previous prime is 142111413053. The next prime is 142111413137. The reversal of 142111413133 is 331314111241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120227240644 + 21884172489 = 346738^2 + 147933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142111413133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142111413098 and 142111413107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142111413137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71055706566 + 71055706567.

It is an arithmetic number, because the mean of its divisors is an integer number (71055706567).

Almost surely, 2142111413133 is an apocalyptic number.

It is an amenable number.

142111413133 is a deficient number, since it is larger than the sum of its proper divisors (1).

142111413133 is an equidigital number, since it uses as much as digits as its factorization.

142111413133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 864, while the sum is 25.

Adding to 142111413133 its reverse (331314111241), we get a palindrome (473425524374).

The spelling of 142111413133 in words is "one hundred forty-two billion, one hundred eleven million, four hundred thirteen thousand, one hundred thirty-three".