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1421120551457 is a prime number
BaseRepresentation
bin10100101011100001011…
…000101011101000100001
312000212011100000222100102
4110223201120223220201
5141240423330121312
63004504225232145
7204446456243555
oct24534130535041
95025140028312
101421120551457
114a876a5591a2
121ab50a492655
13a401b4a98b9
144cad565d865
1526e77470ec2
hex14ae162ba21

1421120551457 has 2 divisors, whose sum is σ = 1421120551458. Its totient is φ = 1421120551456.

The previous prime is 1421120551453. The next prime is 1421120551471. The reversal of 1421120551457 is 7541550211241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1079072198656 + 342048352801 = 1038784^2 + 584849^2 .

It is a cyclic number.

It is not a de Polignac number, because 1421120551457 - 22 = 1421120551453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1421120551457.

It is not a weakly prime, because it can be changed into another prime (1421120551451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710560275728 + 710560275729.

It is an arithmetic number, because the mean of its divisors is an integer number (710560275729).

Almost surely, 21421120551457 is an apocalyptic number.

It is an amenable number.

1421120551457 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421120551457 is an equidigital number, since it uses as much as digits as its factorization.

1421120551457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56000, while the sum is 38.

Adding to 1421120551457 its reverse (7541550211241), we get a palindrome (8962670762698).

The spelling of 1421120551457 in words is "one trillion, four hundred twenty-one billion, one hundred twenty million, five hundred fifty-one thousand, four hundred fifty-seven".