Base | Representation |
---|---|
bin | 10100101011100010101… |
… | …111001000100000000011 |
3 | 12000212012220200100121221 |
4 | 110223202233020200003 |
5 | 141241000130322313 |
6 | 3004510355055511 |
7 | 204450153002425 |
oct | 24534257104003 |
9 | 5025186610557 |
10 | 1421143214083 |
11 | 4a8781327a3a |
12 | 1ab515ba1597 |
13 | a40230b2c38 |
14 | 4cad867c815 |
15 | 26e7944ac8d |
hex | 14ae2bc8803 |
1421143214083 has 2 divisors, whose sum is σ = 1421143214084. Its totient is φ = 1421143214082.
The previous prime is 1421143214081. The next prime is 1421143214119. The reversal of 1421143214083 is 3804123411241.
It is a weak prime.
It is an emirp because it is prime and its reverse (3804123411241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1421143214083 - 21 = 1421143214081 is a prime.
Together with 1421143214081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1421143214081) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710571607041 + 710571607042.
It is an arithmetic number, because the mean of its divisors is an integer number (710571607042).
Almost surely, 21421143214083 is an apocalyptic number.
1421143214083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1421143214083 is an equidigital number, since it uses as much as digits as its factorization.
1421143214083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 34.
The spelling of 1421143214083 in words is "one trillion, four hundred twenty-one billion, one hundred forty-three million, two hundred fourteen thousand, eighty-three".
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