Base | Representation |
---|---|
bin | 1100111011010000010010… |
… | …0110100111011111010110 |
3 | 1212022122222100200101120212 |
4 | 3032310010212213133112 |
5 | 3330322412221431200 |
6 | 50120543140525422 |
7 | 2664535452622550 |
oct | 316640446473726 |
9 | 55278870611525 |
10 | 14212124014550 |
11 | 458a367551420 |
12 | 17164a36b0872 |
13 | 7c1275008c17 |
14 | 371c288104d0 |
15 | 199a5393d035 |
hex | ced049a77d6 |
14212124014550 has 192 divisors, whose sum is σ = 33083221824000. Its totient is φ = 4412869632000.
The previous prime is 14212124014537. The next prime is 14212124014579. The reversal of 14212124014550 is 5541042121241.
It is a super-2 number, since 2×142121240145502 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1108497140 + ... + 1108509960.
It is an arithmetic number, because the mean of its divisors is an integer number (172308447000).
Almost surely, 214212124014550 is an apocalyptic number.
14212124014550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14212124014550 is an abundant number, since it is smaller than the sum of its proper divisors (18871097809450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14212124014550 is a wasteful number, since it uses less digits than its factorization.
14212124014550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13927 (or 13922 counting only the distinct ones).
The product of its (nonzero) digits is 12800, while the sum is 32.
Adding to 14212124014550 its reverse (5541042121241), we get a palindrome (19753166135791).
The spelling of 14212124014550 in words is "fourteen trillion, two hundred twelve billion, one hundred twenty-four million, fourteen thousand, five hundred fifty".
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