Base | Representation |
---|---|
bin | 1100111011010001000110… |
… | …1101011101011111011011 |
3 | 1212022200112200110100202002 |
4 | 3032310101231131133123 |
5 | 3330323340020144121 |
6 | 50121021034031215 |
7 | 2664544063002311 |
oct | 316642155353733 |
9 | 55280480410662 |
10 | 14212343912411 |
11 | 458a46a694997 |
12 | 171654527850b |
13 | 7c12ab73bcb8 |
14 | 371c49ad20b1 |
15 | 199a67dc7e0b |
hex | ced11b5d7db |
14212343912411 has 2 divisors, whose sum is σ = 14212343912412. Its totient is φ = 14212343912410.
The previous prime is 14212343912399. The next prime is 14212343912413. The reversal of 14212343912411 is 11421934321241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14212343912411 - 210 = 14212343911387 is a prime.
It is a Sophie Germain prime.
Together with 14212343912413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14212343912413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106171956205 + 7106171956206.
It is an arithmetic number, because the mean of its divisors is an integer number (7106171956206).
Almost surely, 214212343912411 is an apocalyptic number.
14212343912411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212343912411 is an equidigital number, since it uses as much as digits as its factorization.
14212343912411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 38.
The spelling of 14212343912411 in words is "fourteen trillion, two hundred twelve billion, three hundred forty-three million, nine hundred twelve thousand, four hundred eleven".
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