Base | Representation |
---|---|
bin | 11010011110010000… |
… | …01010000101111011 |
3 | 1100200111012210002002 |
4 | 31033020022011323 |
5 | 213101341043233 |
6 | 10310141531215 |
7 | 1012124515265 |
oct | 151710120573 |
9 | 40614183062 |
10 | 14212440443 |
11 | 6033608953 |
12 | 2907873b0b |
13 | 1456630796 |
14 | 98b7b6b35 |
15 | 582ae86e8 |
hex | 34f20a17b |
14212440443 has 2 divisors, whose sum is σ = 14212440444. Its totient is φ = 14212440442.
The previous prime is 14212440433. The next prime is 14212440457. The reversal of 14212440443 is 34404421241.
14212440443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14212440443 - 212 = 14212436347 is a prime.
It is a super-3 number, since 3×142124404433 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14212440413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106220221 + 7106220222.
It is an arithmetic number, because the mean of its divisors is an integer number (7106220222).
Almost surely, 214212440443 is an apocalyptic number.
14212440443 is a deficient number, since it is larger than the sum of its proper divisors (1).
14212440443 is an equidigital number, since it uses as much as digits as its factorization.
14212440443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 29.
Adding to 14212440443 its reverse (34404421241), we get a palindrome (48616861684).
The spelling of 14212440443 in words is "fourteen billion, two hundred twelve million, four hundred forty thousand, four hundred forty-three".
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