Base | Representation |
---|---|
bin | 1000010001011101000… |
… | …1100100111011100011 |
3 | 111120211220010210210112 |
4 | 2010113101210323203 |
5 | 4312032321420301 |
6 | 145142511121535 |
7 | 13160655335201 |
oct | 2042721447343 |
9 | 446756123715 |
10 | 142124404451 |
11 | 553025806a7 |
12 | 236652132ab |
13 | 1052ca45c53 |
14 | 6c4382c071 |
15 | 3a6c4a99bb |
hex | 2117464ee3 |
142124404451 has 2 divisors, whose sum is σ = 142124404452. Its totient is φ = 142124404450.
The previous prime is 142124404381. The next prime is 142124404483. The reversal of 142124404451 is 154404421241.
It is an a-pointer prime, because the next prime (142124404483) can be obtained adding 142124404451 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142124404451 is a prime.
It is a super-2 number, since 2×1421244044512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (142124404151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71062202225 + 71062202226.
It is an arithmetic number, because the mean of its divisors is an integer number (71062202226).
Almost surely, 2142124404451 is an apocalyptic number.
142124404451 is a deficient number, since it is larger than the sum of its proper divisors (1).
142124404451 is an equidigital number, since it uses as much as digits as its factorization.
142124404451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20480, while the sum is 32.
Adding to 142124404451 its reverse (154404421241), we get a palindrome (296528825692).
The spelling of 142124404451 in words is "one hundred forty-two billion, one hundred twenty-four million, four hundred four thousand, four hundred fifty-one".
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