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1421252351 is a prime number
BaseRepresentation
bin101010010110110…
…1001011011111111
310200001100002200222
41110231221123333
510402320033401
6353010211555
750135305601
oct12455513377
93601302628
101421252351
1166a294a22
12337b83bbb
131985acc2c
14d6a85171
1584b91c1b
hex54b696ff

1421252351 has 2 divisors, whose sum is σ = 1421252352. Its totient is φ = 1421252350.

The previous prime is 1421252341. The next prime is 1421252353. The reversal of 1421252351 is 1532521241.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1421252351 is a prime.

Together with 1421252353, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1421252351.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1421252353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 710626175 + 710626176.

It is an arithmetic number, because the mean of its divisors is an integer number (710626176).

Almost surely, 21421252351 is an apocalyptic number.

1421252351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1421252351 is an equidigital number, since it uses as much as digits as its factorization.

1421252351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2400, while the sum is 26.

The square root of 1421252351 is about 37699.5006730858. The cubic root of 1421252351 is about 1124.3211973541.

Adding to 1421252351 its reverse (1532521241), we get a palindrome (2953773592).

The spelling of 1421252351 in words is "one billion, four hundred twenty-one million, two hundred fifty-two thousand, three hundred fifty-one".