Base | Representation |
---|---|
bin | 11010011110010101… |
… | …10000000001100110 |
3 | 1100200112111022101122 |
4 | 31033022300001212 |
5 | 213102024320402 |
6 | 10310204253542 |
7 | 1012133345636 |
oct | 151712600146 |
9 | 40615438348 |
10 | 14213120102 |
11 | 6033a32555 |
12 | 2907b412b2 |
13 | 145680ac4c |
14 | 98b9126c6 |
15 | 582bceca2 |
hex | 34f2b0066 |
14213120102 has 4 divisors (see below), whose sum is σ = 21319680156. Its totient is φ = 7106560050.
The previous prime is 14213120101. The next prime is 14213120123. The reversal of 14213120102 is 20102131241.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14213120101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3553280024 + ... + 3553280027.
It is an arithmetic number, because the mean of its divisors is an integer number (5329920039).
Almost surely, 214213120102 is an apocalyptic number.
14213120102 is a deficient number, since it is larger than the sum of its proper divisors (7106560054).
14213120102 is an equidigital number, since it uses as much as digits as its factorization.
14213120102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7106560053.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 14213120102 its reverse (20102131241), we get a palindrome (34315251343).
The spelling of 14213120102 in words is "fourteen billion, two hundred thirteen million, one hundred twenty thousand, one hundred two".
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