142131343413131 has 2 divisors, whose sum is σ = 142131343413132. Its totient is φ = 142131343413130.

The previous prime is 142131343413061. The next prime is 142131343413133. The reversal of 142131343413131 is 131314343131241.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 142131343413131 - 2²⁶ = 142131276304267 is a prime.

It is a super-2 number, since 2×142131343413131² (a number of 29 digits) contains 22 as substring.

Together with 142131343413133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142131343413091 and 142131343413100.

It is not a weakly prime, because it can be changed into another prime (142131343413133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71065671706565 + 71065671706566.

It is an arithmetic number, because the mean of its divisors is an integer number (71065671706566).

Almost surely, 2^{142131343413131} is an apocalyptic number.

142131343413131 is a deficient number, since it is larger than the sum of its proper divisors (1).

142131343413131 is an equidigital number, since it uses as much as digits as its factorization.

142131343413131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 31104, while the sum is 35.

Adding to 142131343413131 its reverse (131314343131241), we get a palindrome (273445686544372).

The spelling of 142131343413131 in words is "one hundred forty-two trillion, one hundred thirty-one billion, three hundred forty-three million, four hundred thirteen thousand, one hundred thirty-one".