14213144404421 has 2 divisors, whose sum is σ = 14213144404422. Its totient is φ = 14213144404420.

The previous prime is 14213144404369. The next prime is 14213144404423. The reversal of 14213144404421 is 12440444131241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12910439472100 + 1302704932321 = 3593110^2 + 1141361^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14213144404421 is a prime.

It is a Sophie Germain prime.

Together with 14213144404423, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14213144404423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106572202210 + 7106572202211.

It is an arithmetic number, because the mean of its divisors is an integer number (7106572202211).

Almost surely, 2^{14213144404421} is an apocalyptic number.

It is an amenable number.

14213144404421 is a deficient number, since it is larger than the sum of its proper divisors (1).

14213144404421 is an equidigital number, since it uses as much as digits as its factorization.

14213144404421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49152, while the sum is 35.

Adding to 14213144404421 its reverse (12440444131241), we get a palindrome (26653588535662).

The spelling of 14213144404421 in words is "fourteen trillion, two hundred thirteen billion, one hundred forty-four million, four hundred four thousand, four hundred twenty-one".