142133120021 has 2 divisors, whose sum is σ = 142133120022. Its totient is φ = 142133120020.

The previous prime is 142133119991. The next prime is 142133120023. The reversal of 142133120021 is 120021331241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125450556100 + 16682563921 = 354190^2 + 129161^2 .

It is a cyclic number.

It is not a de Polignac number, because 142133120021 - 2¹⁰ = 142133118997 is a prime.

Together with 142133120023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 142133119975 and 142133120002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142133120023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71066560010 + 71066560011.

It is an arithmetic number, because the mean of its divisors is an integer number (71066560011).

Almost surely, 2^142133120021 is an apocalyptic number.

It is an amenable number.

142133120021 is a deficient number, since it is larger than the sum of its proper divisors (1).

142133120021 is an equidigital number, since it uses as much as digits as its factorization.

142133120021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 142133120021 its reverse (120021331241), we get a palindrome (262154451262).

The spelling of 142133120021 in words is "one hundred forty-two billion, one hundred thirty-three million, one hundred twenty thousand, twenty-one".