Base | Representation |
---|---|
bin | 11010011110010111… |
… | …10011100111011101 |
3 | 1100200120000101011112 |
4 | 31033023303213131 |
5 | 213102112200312 |
6 | 10310214231405 |
7 | 1012135611044 |
oct | 151713634735 |
9 | 40616011145 |
10 | 14213396957 |
11 | 6034101561 |
12 | 2908055565 |
13 | 14568a6c76 |
14 | 98b98555b |
15 | 582c36d22 |
hex | 34f2f39dd |
14213396957 has 2 divisors, whose sum is σ = 14213396958. Its totient is φ = 14213396956.
The previous prime is 14213396909. The next prime is 14213396959. The reversal of 14213396957 is 75969331241.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13738418521 + 474978436 = 117211^2 + 21794^2 .
It is a cyclic number.
It is not a de Polignac number, because 14213396957 - 26 = 14213396893 is a prime.
Together with 14213396959, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14213396959) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7106698478 + 7106698479.
It is an arithmetic number, because the mean of its divisors is an integer number (7106698479).
Almost surely, 214213396957 is an apocalyptic number.
It is an amenable number.
14213396957 is a deficient number, since it is larger than the sum of its proper divisors (1).
14213396957 is an equidigital number, since it uses as much as digits as its factorization.
14213396957 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1224720, while the sum is 50.
The spelling of 14213396957 in words is "fourteen billion, two hundred thirteen million, three hundred ninety-six thousand, nine hundred fifty-seven".
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