14213413040 has 120 divisors (see below), whose sum is σ = 36632075040. Its totient is φ = 5118091264.

The previous prime is 14213413033. The next prime is 14213413073. The reversal of 14213413040 is 4031431241.

It is a super-2 number, since 2×14213413040² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (23).

It is a junction number, because it is equal to n+sod(n) for n = 14213412997 and 14213413015.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 518396 + ... + 545124.

It is an arithmetic number, because the mean of its divisors is an integer number (305267292).

Almost surely, 2^14213413040 is an apocalyptic number.

14213413040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14213413040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18316037520).

14213413040 is an abundant number, since it is smaller than the sum of its proper divisors (22418662000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14213413040 is a wasteful number, since it uses less digits than its factorization.

14213413040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26799 (or 26776 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14213413040 its reverse (4031431241), we get a palindrome (18244844281).

The spelling of 14213413040 in words is "fourteen billion, two hundred thirteen million, four hundred thirteen thousand, forty".