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14214113120401 is a prime number
BaseRepresentation
bin1100111011010111101100…
…1010011101000010010001
31212022212002222112102211221
43032311323022131002101
53330341000424323101
650121512354205041
72664635655012145
oct316657312350221
955285088472757
1014214113120401
114590198328057
121716959883781
137c150113a72c
14371d76a71225
15199b1d39caa1
hexced7b29d091

14214113120401 has 2 divisors, whose sum is σ = 14214113120402. Its totient is φ = 14214113120400.

The previous prime is 14214113120399. The next prime is 14214113120437. The reversal of 14214113120401 is 10402131141241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13934721589776 + 279391530625 = 3732924^2 + 528575^2 .

It is a cyclic number.

It is not a de Polignac number, because 14214113120401 - 21 = 14214113120399 is a prime.

Together with 14214113120399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (14244113120401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107056560200 + 7107056560201.

It is an arithmetic number, because the mean of its divisors is an integer number (7107056560201).

Almost surely, 214214113120401 is an apocalyptic number.

It is an amenable number.

14214113120401 is a deficient number, since it is larger than the sum of its proper divisors (1).

14214113120401 is an equidigital number, since it uses as much as digits as its factorization.

14214113120401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14214113120401 its reverse (10402131141241), we get a palindrome (24616244261642).

The spelling of 14214113120401 in words is "fourteen trillion, two hundred fourteen billion, one hundred thirteen million, one hundred twenty thousand, four hundred one".