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14214124402333 is a prime number
BaseRepresentation
bin1100111011010111101111…
…0101011111011010011101
31212022212010202202121202021
43032311323311133122131
53330341011321333313
650121513440100141
72664636152631112
oct316657365373235
955285122677667
1014214124402333
1145901a3733369
121716961604651
137c150358a92b
14371d7836a909
15199b1e37a78d
hexced7bd5f69d

14214124402333 has 2 divisors, whose sum is σ = 14214124402334. Its totient is φ = 14214124402332.

The previous prime is 14214124402249. The next prime is 14214124402349. The reversal of 14214124402333 is 33320442141241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13506705471609 + 707418930724 = 3675147^2 + 841082^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14214124402333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14214124472333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107062201166 + 7107062201167.

It is an arithmetic number, because the mean of its divisors is an integer number (7107062201167).

Almost surely, 214214124402333 is an apocalyptic number.

It is an amenable number.

14214124402333 is a deficient number, since it is larger than the sum of its proper divisors (1).

14214124402333 is an equidigital number, since it uses as much as digits as its factorization.

14214124402333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 14214124402333 its reverse (33320442141241), we get a palindrome (47534566543574).

The spelling of 14214124402333 in words is "fourteen trillion, two hundred fourteen billion, one hundred twenty-four million, four hundred two thousand, three hundred thirty-three".