Base | Representation |
---|---|
bin | 1100111011011000000100… |
… | …0111111000100100000111 |
3 | 1212022212100221200102211021 |
4 | 3032312001013320210013 |
5 | 3330341202024010043 |
6 | 50121530325252011 |
7 | 2664641310632113 |
oct | 316660107704407 |
9 | 55285327612737 |
10 | 14214213110023 |
11 | 4590239811803 |
12 | 1716987264007 |
13 | 7c1518a795a4 |
14 | 371d8605c743 |
15 | 199b2704e3ed |
hex | ced811f8907 |
14214213110023 has 2 divisors, whose sum is σ = 14214213110024. Its totient is φ = 14214213110022.
The previous prime is 14214213109981. The next prime is 14214213110089. The reversal of 14214213110023 is 32001131241241.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14214213110023 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14214213110023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14214213110423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7107106555011 + 7107106555012.
It is an arithmetic number, because the mean of its divisors is an integer number (7107106555012).
Almost surely, 214214213110023 is an apocalyptic number.
14214213110023 is a deficient number, since it is larger than the sum of its proper divisors (1).
14214213110023 is an equidigital number, since it uses as much as digits as its factorization.
14214213110023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14214213110023 its reverse (32001131241241), we get a palindrome (46215344351264).
The spelling of 14214213110023 in words is "fourteen trillion, two hundred fourteen billion, two hundred thirteen million, one hundred ten thousand, twenty-three".
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