Search a number
-
+
1421531243500 = 22532843062487
BaseRepresentation
bin10100101011111001110…
…111010110001111101100
312000220012221211021220211
4110223321313112033230
5141242243444243000
63005013055552204
7204462604126504
oct24537167261754
95026187737824
101421531243500
114a8960367205
121ab603b2b664
13a40855c2a44
144cb34008a04
1526e9d5477ba
hex14af9dd63ec

1421531243500 has 24 divisors (see below), whose sum is σ = 3104624236896. Its totient is φ = 568612497200.

The previous prime is 1421531243491. The next prime is 1421531243513. The reversal of 1421531243500 is 53421351241.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1421530744 + ... + 1421531743.

It is an arithmetic number, because the mean of its divisors is an integer number (129359343204).

Almost surely, 21421531243500 is an apocalyptic number.

1421531243500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1421531243500 is an abundant number, since it is smaller than the sum of its proper divisors (1683092993396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1421531243500 is a wasteful number, since it uses less digits than its factorization.

1421531243500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2843062506 (or 2843062494 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1421531243500 its reverse (53421351241), we get a palindrome (1474952594741).

The spelling of 1421531243500 in words is "one trillion, four hundred twenty-one billion, five hundred thirty-one million, two hundred forty-three thousand, five hundred".

Divisors: 1 2 4 5 10 20 25 50 100 125 250 500 2843062487 5686124974 11372249948 14215312435 28430624870 56861249740 71076562175 142153124350 284306248700 355382810875 710765621750 1421531243500