14220131111 has 2 divisors, whose sum is σ = 14220131112. Its totient is φ = 14220131110.

The previous prime is 14220131059. The next prime is 14220131113. The reversal of 14220131111 is 11113102241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14220131111 - 2³⁰ = 13146389287 is a prime.

It is a Sophie Germain prime.

Together with 14220131113, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14220131111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14220131113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110065555 + 7110065556.

It is an arithmetic number, because the mean of its divisors is an integer number (7110065556).

Almost surely, 2^14220131111 is an apocalyptic number.

14220131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14220131111 is an equidigital number, since it uses as much as digits as its factorization.

14220131111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 14220131111 its reverse (11113102241), we get a palindrome (25333233352).

The spelling of 14220131111 in words is "fourteen billion, two hundred twenty million, one hundred thirty-one thousand, one hundred eleven".