Base | Representation |
---|---|
bin | 1000010001101111101… |
… | …1001010111111010111 |
3 | 111121001022221021001022 |
4 | 2010123323022333113 |
5 | 4312212304321421 |
6 | 145154335151355 |
7 | 13162623413306 |
oct | 2043373127727 |
9 | 447038837038 |
10 | 142202417111 |
11 | 55342614777 |
12 | 2368737555b |
13 | 10542c5b8a1 |
14 | 6c4dd3843d |
15 | 3a742697ab |
hex | 211becafd7 |
142202417111 has 2 divisors, whose sum is σ = 142202417112. Its totient is φ = 142202417110.
The previous prime is 142202417107. The next prime is 142202417113. The reversal of 142202417111 is 111714202241.
It is a strong prime.
It is an emirp because it is prime and its reverse (111714202241) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 142202417111 - 22 = 142202417107 is a prime.
Together with 142202417113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142202417113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71101208555 + 71101208556.
It is an arithmetic number, because the mean of its divisors is an integer number (71101208556).
Almost surely, 2142202417111 is an apocalyptic number.
142202417111 is a deficient number, since it is larger than the sum of its proper divisors (1).
142202417111 is an equidigital number, since it uses as much as digits as its factorization.
142202417111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 26.
Adding to 142202417111 its reverse (111714202241), we get a palindrome (253916619352).
The spelling of 142202417111 in words is "one hundred forty-two billion, two hundred two million, four hundred seventeen thousand, one hundred eleven".
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