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14221134135007 is a prime number
BaseRepresentation
bin1100111011110001110110…
…1001011111111011011111
31212100112020021210221020221
43032330131221133323133
53330444340314310012
650125033203022211
72665304650444402
oct316743551377337
955315207727227
1014221134135007
114593170525268
12171819906a967
137c207c8c0847
143724412dbd39
15199dce968507
hexcef1da5fedf

14221134135007 has 2 divisors, whose sum is σ = 14221134135008. Its totient is φ = 14221134135006.

The previous prime is 14221134134953. The next prime is 14221134135029. The reversal of 14221134135007 is 70053143112241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14221134135007 - 239 = 13671378321119 is a prime.

It is a super-3 number, since 3×142211341350073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14221134135067) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7110567067503 + 7110567067504.

It is an arithmetic number, because the mean of its divisors is an integer number (7110567067504).

Almost surely, 214221134135007 is an apocalyptic number.

14221134135007 is a deficient number, since it is larger than the sum of its proper divisors (1).

14221134135007 is an equidigital number, since it uses as much as digits as its factorization.

14221134135007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 34.

Adding to 14221134135007 its reverse (70053143112241), we get a palindrome (84274277247248).

The spelling of 14221134135007 in words is "fourteen trillion, two hundred twenty-one billion, one hundred thirty-four million, one hundred thirty-five thousand, seven".