Base | Representation |
---|---|
bin | 1000010001110010010… |
… | …0000101111011101111 |
3 | 111121002002010020222201 |
4 | 2010130210011323233 |
5 | 4312223031104203 |
6 | 145155401122331 |
7 | 13163113532026 |
oct | 2043444057357 |
9 | 447062106881 |
10 | 142213144303 |
11 | 5534868121a |
12 | 2368aa893a7 |
13 | 10545246439 |
14 | 6c5152b8bd |
15 | 3a75187e1d |
hex | 211c905eef |
142213144303 has 2 divisors, whose sum is σ = 142213144304. Its totient is φ = 142213144302.
The previous prime is 142213144267. The next prime is 142213144351. The reversal of 142213144303 is 303441312241.
It is a happy number.
142213144303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142213144303 - 29 = 142213143791 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142213144903) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71106572151 + 71106572152.
It is an arithmetic number, because the mean of its divisors is an integer number (71106572152).
Almost surely, 2142213144303 is an apocalyptic number.
142213144303 is a deficient number, since it is larger than the sum of its proper divisors (1).
142213144303 is an equidigital number, since it uses as much as digits as its factorization.
142213144303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 142213144303 its reverse (303441312241), we get a palindrome (445654456544).
The spelling of 142213144303 in words is "one hundred forty-two billion, two hundred thirteen million, one hundred forty-four thousand, three hundred three".
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