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14223200300017 is a prime number
BaseRepresentation
bin1100111011111001100011…
…0011010010101111110001
31212100201120021122222210221
43032332120303102233301
53331013103234100032
650130014212053041
72665410106531162
oct316763063225761
955321507588727
1014223200300017
114594030853655
121718675004181
137c231b992ca7
1437259989b769
15199ea104a597
hexcef98cd2bf1

14223200300017 has 2 divisors, whose sum is σ = 14223200300018. Its totient is φ = 14223200300016.

The previous prime is 14223200299963. The next prime is 14223200300039. The reversal of 14223200300017 is 71000300232241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13723349886016 + 499850414001 = 3704504^2 + 707001^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14223200300017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14223200299964 and 14223200300000.

It is not a weakly prime, because it can be changed into another prime (14223200303017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111600150008 + 7111600150009.

It is an arithmetic number, because the mean of its divisors is an integer number (7111600150009).

Almost surely, 214223200300017 is an apocalyptic number.

It is an amenable number.

14223200300017 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223200300017 is an equidigital number, since it uses as much as digits as its factorization.

14223200300017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 14223200300017 its reverse (71000300232241), we get a palindrome (85223500532258).

The spelling of 14223200300017 in words is "fourteen trillion, two hundred twenty-three billion, two hundred million, three hundred thousand, seventeen".