Base | Representation |
---|---|
bin | 1100111011111001101010… |
… | …1001101010111101101111 |
3 | 1212100201122110001120222022 |
4 | 3032332122221222331233 |
5 | 3331013134210112312 |
6 | 50130021241140355 |
7 | 2665410634356062 |
oct | 316763251527557 |
9 | 55321573046868 |
10 | 14223231332207 |
11 | 4594047319597 |
12 | 171868348a6bb |
13 | 7c2325239a31 |
14 | 37259da588d9 |
15 | 199ea3b2a172 |
hex | cef9aa6af6f |
14223231332207 has 2 divisors, whose sum is σ = 14223231332208. Its totient is φ = 14223231332206.
The previous prime is 14223231332179. The next prime is 14223231332209. The reversal of 14223231332207 is 70223313232241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14223231332207 is a prime.
Together with 14223231332209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14223231332209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111615666103 + 7111615666104.
It is an arithmetic number, because the mean of its divisors is an integer number (7111615666104).
Almost surely, 214223231332207 is an apocalyptic number.
14223231332207 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223231332207 is an equidigital number, since it uses as much as digits as its factorization.
14223231332207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576, while the sum is 35.
Adding to 14223231332207 its reverse (70223313232241), we get a palindrome (84446544564448).
The spelling of 14223231332207 in words is "fourteen trillion, two hundred twenty-three billion, two hundred thirty-one million, three hundred thirty-two thousand, two hundred seven".
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