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14223442121143 is a prime number
BaseRepresentation
bin1100111011111010011100…
…1101110001000110110111
31212100202012010200210000221
43032332213031301012313
53331014102140334033
650130054211115211
72665416104140063
oct316764715610667
955322163623027
1014223442121143
114594145300422
121718721ba2b07
137c2359b00a08
143725bda48aa3
15199eb73b612d
hexcefa73711b7

14223442121143 has 2 divisors, whose sum is σ = 14223442121144. Its totient is φ = 14223442121142.

The previous prime is 14223442121107. The next prime is 14223442121159. The reversal of 14223442121143 is 34112124432241.

It is a strong prime.

It is an emirp because it is prime and its reverse (34112124432241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14223442121143 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14223442121099 and 14223442121108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14223442121173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111721060571 + 7111721060572.

It is an arithmetic number, because the mean of its divisors is an integer number (7111721060572).

Almost surely, 214223442121143 is an apocalyptic number.

14223442121143 is a deficient number, since it is larger than the sum of its proper divisors (1).

14223442121143 is an equidigital number, since it uses as much as digits as its factorization.

14223442121143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 36864, while the sum is 34.

Adding to 14223442121143 its reverse (34112124432241), we get a palindrome (48335566553384).

The spelling of 14223442121143 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-two million, one hundred twenty-one thousand, one hundred forty-three".