Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …1101110001000111110111 |
3 | 1212100202012010200210010022 |
4 | 3032332213031301013313 |
5 | 3331014102140334312 |
6 | 50130054211115355 |
7 | 2665416104140214 |
oct | 316764715610767 |
9 | 55322163623108 |
10 | 14223442121207 |
11 | 4594145300480 |
12 | 1718721ba2b5b |
13 | 7c2359b00a57 |
14 | 3725bda48b0b |
15 | 199eb73b6172 |
hex | cefa73711f7 |
14223442121207 has 32 divisors (see below), whose sum is σ = 16568570912256. Its totient is φ = 12079905868800.
The previous prime is 14223442121183. The next prime is 14223442121257. The reversal of 14223442121207 is 70212124432241.
It is a happy number.
It is not a de Polignac number, because 14223442121207 - 26 = 14223442121143 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14223442121257) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 354211043 + ... + 354251195.
It is an arithmetic number, because the mean of its divisors is an integer number (517767841008).
Almost surely, 214223442121207 is an apocalyptic number.
14223442121207 is a deficient number, since it is larger than the sum of its proper divisors (2345128791049).
14223442121207 is a wasteful number, since it uses less digits than its factorization.
14223442121207 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72791.
The product of its (nonzero) digits is 43008, while the sum is 35.
Adding to 14223442121207 its reverse (70212124432241), we get a palindrome (84435566553448).
The spelling of 14223442121207 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-two million, one hundred twenty-one thousand, two hundred seven".
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