Base | Representation |
---|---|
bin | 1100111011111010011100… |
… | …1101110001001011000011 |
3 | 1212100202012010200210101212 |
4 | 3032332213031301023003 |
5 | 3331014102140341121 |
6 | 50130054211120335 |
7 | 2665416104140625 |
oct | 316764715611303 |
9 | 55322163623355 |
10 | 14223442121411 |
11 | 4594145300646 |
12 | 1718721ba30ab |
13 | 7c2359b00b83 |
14 | 3725bda48c15 |
15 | 199eb73b625b |
hex | cefa73712c3 |
14223442121411 has 2 divisors, whose sum is σ = 14223442121412. Its totient is φ = 14223442121410.
The previous prime is 14223442121377. The next prime is 14223442121429. The reversal of 14223442121411 is 11412124432241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14223442121411 - 210 = 14223442120387 is a prime.
It is a super-2 number, since 2×142234421214112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14223442121611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7111721060705 + 7111721060706.
It is an arithmetic number, because the mean of its divisors is an integer number (7111721060706).
Almost surely, 214223442121411 is an apocalyptic number.
14223442121411 is a deficient number, since it is larger than the sum of its proper divisors (1).
14223442121411 is an equidigital number, since it uses as much as digits as its factorization.
14223442121411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12288, while the sum is 32.
Adding to 14223442121411 its reverse (11412124432241), we get a palindrome (25635566553652).
The spelling of 14223442121411 in words is "fourteen trillion, two hundred twenty-three billion, four hundred forty-two million, one hundred twenty-one thousand, four hundred eleven".
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