Base | Representation |
---|---|
bin | 1100111011111100111001… |
… | …1011111001001000000111 |
3 | 1212100210212222212100221111 |
4 | 3032333032123321020013 |
5 | 3331021424113313211 |
6 | 50130243354425451 |
7 | 2665441314153064 |
oct | 316771633711007 |
9 | 55323788770844 |
10 | 14224100135431 |
11 | 459445278328a |
12 | 1718886432287 |
13 | 7c243322c794 |
14 | 3726431b3c6b |
15 | 19a005043421 |
hex | cefce6f9207 |
14224100135431 has 2 divisors, whose sum is σ = 14224100135432. Its totient is φ = 14224100135430.
The previous prime is 14224100135369. The next prime is 14224100135447. The reversal of 14224100135431 is 13453100142241.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14224100135431 - 29 = 14224100134919 is a prime.
It is a super-2 number, since 2×142241001354312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14224100135393 and 14224100135402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14224100130431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7112050067715 + 7112050067716.
It is an arithmetic number, because the mean of its divisors is an integer number (7112050067716).
Almost surely, 214224100135431 is an apocalyptic number.
14224100135431 is a deficient number, since it is larger than the sum of its proper divisors (1).
14224100135431 is an equidigital number, since it uses as much as digits as its factorization.
14224100135431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 14224100135431 its reverse (13453100142241), we get a palindrome (27677200277672).
The spelling of 14224100135431 in words is "fourteen trillion, two hundred twenty-four billion, one hundred million, one hundred thirty-five thousand, four hundred thirty-one".
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