Base | Representation |
---|---|
bin | 100000010101111000011101… |
… | …011001011010101011011111 |
3 | 200122122010110012021200022002 |
4 | 200111320131121122223133 |
5 | 122120440004322023241 |
6 | 1222304414152112515 |
7 | 41650406014641104 |
oct | 4025703531325337 |
9 | 618563405250262 |
10 | 142241220111071 |
11 | 41360187593824 |
12 | 13b5337499573b |
13 | 614a39c05c7b3 |
14 | 271a7244b2aab |
15 | 116a0495d489b |
hex | 815e1d65aadf |
142241220111071 has 2 divisors, whose sum is σ = 142241220111072. Its totient is φ = 142241220111070.
The previous prime is 142241220111047. The next prime is 142241220111149. The reversal of 142241220111071 is 170111022142241.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 142241220111071 - 26 = 142241220111007 is a prime.
It is a super-2 number, since 2×1422412201110712 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142241220111041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71120610055535 + 71120610055536.
It is an arithmetic number, because the mean of its divisors is an integer number (71120610055536).
Almost surely, 2142241220111071 is an apocalyptic number.
142241220111071 is a deficient number, since it is larger than the sum of its proper divisors (1).
142241220111071 is an equidigital number, since it uses as much as digits as its factorization.
142241220111071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1792, while the sum is 29.
The spelling of 142241220111071 in words is "one hundred forty-two trillion, two hundred forty-one billion, two hundred twenty million, one hundred eleven thousand, seventy-one".
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