1422412446650 has 24 divisors (see below), whose sum is σ = 2849201548284. Its totient is φ = 525198441600.

The previous prime is 1422412446619. The next prime is 1422412446701. The reversal of 1422412446650 is 566442142241.

It can be written as a sum of positive squares in 6 ways, for example, as 174238621561 + 1248173825089 = 417419^2 + 1117217^2 .

It is a super-3 number, since 3×1422412446650³ (a number of 37 digits) contains 333 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1422412446598 and 1422412446607.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1094162771 + ... + 1094164070.

Almost surely, 2^{1422412446650} is an apocalyptic number.

1422412446650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1422412446650 is an abundant number, since it is smaller than the sum of its proper divisors (1426789101634).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1422412446650 is a wasteful number, since it uses less digits than its factorization.

1422412446650 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2188326866 (or 2188326861 counting only the distinct ones).

The product of its (nonzero) digits is 368640, while the sum is 41.

Adding to 1422412446650 its reverse (566442142241), we get a palindrome (1988854588891).

The spelling of 1422412446650 in words is "one trillion, four hundred twenty-two billion, four hundred twelve million, four hundred forty-six thousand, six hundred fifty".