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142242520253 is a prime number
BaseRepresentation
bin1000010001111001010…
…0001001110010111101
3111121011010101201012212
42010132110021302331
54312303041122003
6145202330510205
713163621321141
oct2043624116275
9447133351185
10142242520253
1155363215869
1223698895365
131054b360362
146c553b7221
153a77a3bdd8
hex211e509cbd

142242520253 has 2 divisors, whose sum is σ = 142242520254. Its totient is φ = 142242520252.

The previous prime is 142242520111. The next prime is 142242520279. The reversal of 142242520253 is 352025242241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140327407609 + 1915112644 = 374603^2 + 43762^2 .

It is an emirp because it is prime and its reverse (352025242241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142242520253 - 210 = 142242519229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142242523253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71121260126 + 71121260127.

It is an arithmetic number, because the mean of its divisors is an integer number (71121260127).

Almost surely, 2142242520253 is an apocalyptic number.

It is an amenable number.

142242520253 is a deficient number, since it is larger than the sum of its proper divisors (1).

142242520253 is an equidigital number, since it uses as much as digits as its factorization.

142242520253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 38400, while the sum is 32.

Adding to 142242520253 its reverse (352025242241), we get a palindrome (494267762494).

The spelling of 142242520253 in words is "one hundred forty-two billion, two hundred forty-two million, five hundred twenty thousand, two hundred fifty-three".