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142250503133 is a prime number
BaseRepresentation
bin1000010001111011001…
…0100110101111011101
3111121011200102021200002
42010132302212233131
54312312112100013
6145203213544045
713164046216634
oct2043662465735
9447150367602
10142250503133
1155367778492
122369b4a5025
131054cbc6a5b
146c5649451b
153a785b7358
hex211eca6bdd

142250503133 has 2 divisors, whose sum is σ = 142250503134. Its totient is φ = 142250503132.

The previous prime is 142250503097. The next prime is 142250503139. The reversal of 142250503133 is 331305052241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 134053373689 + 8197129444 = 366133^2 + 90538^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-142250503133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142250503096 and 142250503105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142250503139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71125251566 + 71125251567.

It is an arithmetic number, because the mean of its divisors is an integer number (71125251567).

Almost surely, 2142250503133 is an apocalyptic number.

It is an amenable number.

142250503133 is a deficient number, since it is larger than the sum of its proper divisors (1).

142250503133 is an equidigital number, since it uses as much as digits as its factorization.

142250503133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 142250503133 its reverse (331305052241), we get a palindrome (473555555374).

The spelling of 142250503133 in words is "one hundred forty-two billion, two hundred fifty million, five hundred three thousand, one hundred thirty-three".