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1422505540117 is a prime number
BaseRepresentation
bin10100101100110011111…
…011111111101000010101
312000222201212010200121201
4110230303323333220111
5141301242404240432
63005253502312501
7204526004405434
oct24546373775025
95028655120551
101422505540117
114a9310324722
121ab836288731
13a41ac40080c
144cbc758511b
1527008d4cee7
hex14b33effa15

1422505540117 has 2 divisors, whose sum is σ = 1422505540118. Its totient is φ = 1422505540116.

The previous prime is 1422505540111. The next prime is 1422505540129. The reversal of 1422505540117 is 7110455052241.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 924124606596 + 498380933521 = 961314^2 + 705961^2 .

It is an emirp because it is prime and its reverse (7110455052241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1422505540117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422505540111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711252770058 + 711252770059.

It is an arithmetic number, because the mean of its divisors is an integer number (711252770059).

Almost surely, 21422505540117 is an apocalyptic number.

It is an amenable number.

1422505540117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422505540117 is an equidigital number, since it uses as much as digits as its factorization.

1422505540117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 56000, while the sum is 37.

The spelling of 1422505540117 in words is "one trillion, four hundred twenty-two billion, five hundred five million, five hundred forty thousand, one hundred seventeen".