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142300041113024 = 262223438142391
BaseRepresentation
bin100000010110101111001111…
…011001101110110111000000
3200122211202021112101011202222
4200112233033121232313000
5122122420441011104044
61222351423022230212
741654560450131524
oct4026571731566700
9618752245334688
10142300041113024
11413831214aa133
1213b6284ba25368
136152ab44699b2
14271d504541d84
15116b83d5998ee
hex816bcf66edc0

142300041113024 has 14 divisors (see below), whose sum is σ = 282376644083784. Its totient is φ = 71150020556480.

The previous prime is 142300041112991. The next prime is 142300041113039. The reversal of 142300041113024 is 420311140003241.

It is a super-4 number, since 4×1423000411130244 (a number of 58 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142300041112984 and 142300041113002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1111719071132 + ... + 1111719071259.

Almost surely, 2142300041113024 is an apocalyptic number.

It is an amenable number.

142300041113024 is a deficient number, since it is larger than the sum of its proper divisors (140076602970760).

142300041113024 is an equidigital number, since it uses as much as digits as its factorization.

142300041113024 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2223438142403 (or 2223438142393 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 142300041113024 its reverse (420311140003241), we get a palindrome (562611181116265).

The spelling of 142300041113024 in words is "one hundred forty-two trillion, three hundred billion, forty-one million, one hundred thirteen thousand, twenty-four".

Divisors: 1 2 4 8 16 32 64 2223438142391 4446876284782 8893752569564 17787505139128 35575010278256 71150020556512 142300041113024