1423040012113 has 2 divisors, whose sum is σ = 1423040012114. Its totient is φ = 1423040012112.

The previous prime is 1423040012111. The next prime is 1423040012123. The reversal of 1423040012113 is 3112100403241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 750940098624 + 672099913489 = 866568^2 + 819817^2 .

It is an emirp because it is prime and its reverse (3112100403241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1423040012113 - 2¹ = 1423040012111 is a prime.

Together with 1423040012111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1423040012111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711520006056 + 711520006057.

It is an arithmetic number, because the mean of its divisors is an integer number (711520006057).

Almost surely, 2^{1423040012113} is an apocalyptic number.

It is an amenable number.

1423040012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423040012113 is an equidigital number, since it uses as much as digits as its factorization.

1423040012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1423040012113 its reverse (3112100403241), we get a palindrome (4535140415354).

The spelling of 1423040012113 in words is "one trillion, four hundred twenty-three billion, forty million, twelve thousand, one hundred thirteen".