1423040012111 has 2 divisors, whose sum is σ = 1423040012112. Its totient is φ = 1423040012110.

The previous prime is 1423040012099. The next prime is 1423040012113. The reversal of 1423040012111 is 1112100403241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1423040012111 - 2³⁰ = 1421966270287 is a prime.

Together with 1423040012113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1423040012113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711520006055 + 711520006056.

It is an arithmetic number, because the mean of its divisors is an integer number (711520006056).

Almost surely, 2^{1423040012111} is an apocalyptic number.

1423040012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423040012111 is an equidigital number, since it uses as much as digits as its factorization.

1423040012111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 1423040012111 its reverse (1112100403241), we get a palindrome (2535140415352).

The spelling of 1423040012111 in words is "one trillion, four hundred twenty-three billion, forty million, twelve thousand, one hundred eleven".