14230441231 has 2 divisors, whose sum is σ = 14230441232. Its totient is φ = 14230441230.

The previous prime is 14230441213. The next prime is 14230441237. The reversal of 14230441231 is 13214403241.

Together with previous prime (14230441213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14230441231 - 2¹¹ = 14230439183 is a prime.

It is a super-2 number, since 2×14230441231² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14230441196 and 14230441205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14230441237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115220615 + 7115220616.

It is an arithmetic number, because the mean of its divisors is an integer number (7115220616).

Almost surely, 2^14230441231 is an apocalyptic number.

14230441231 is a deficient number, since it is larger than the sum of its proper divisors (1).

14230441231 is an equidigital number, since it uses as much as digits as its factorization.

14230441231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14230441231 its reverse (13214403241), we get a palindrome (27444844472).

The spelling of 14230441231 in words is "fourteen billion, two hundred thirty million, four hundred forty-one thousand, two hundred thirty-one".