1423113455333 has 2 divisors, whose sum is σ = 1423113455334. Its totient is φ = 1423113455332.

The previous prime is 1423113455297. The next prime is 1423113455339. The reversal of 1423113455333 is 3335543113241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1410814201729 + 12299253604 = 1187777^2 + 110902^2 .

It is an emirp because it is prime and its reverse (3335543113241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1423113455333 - 2²² = 1423109261029 is a prime.

It is a super-3 number, since 3×1423113455333³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1423113455339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711556727666 + 711556727667.

It is an arithmetic number, because the mean of its divisors is an integer number (711556727667).

Almost surely, 2^{1423113455333} is an apocalyptic number.

It is an amenable number.

1423113455333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1423113455333 is an equidigital number, since it uses as much as digits as its factorization.

1423113455333 is an evil number, because the sum of its binary digits is even.

The product of its digits is 194400, while the sum is 38.

Adding to 1423113455333 its reverse (3335543113241), we get a palindrome (4758656568574).

The spelling of 1423113455333 in words is "one trillion, four hundred twenty-three billion, one hundred thirteen million, four hundred fifty-five thousand, three hundred thirty-three".