Base | Representation |
---|---|
bin | 1100111100010111110000… |
… | …1011011000111100111111 |
3 | 1212101111111110112001120021 |
4 | 3033011330023120330333 |
5 | 3331131210330342343 |
6 | 50133435031233011 |
7 | 2666115062124043 |
oct | 317057413307477 |
9 | 55344443461507 |
10 | 14231310012223 |
11 | 4597512546447 |
12 | 171a158b18767 |
13 | 7c3011b6a475 |
14 | 372b28964023 |
15 | 19a2c7eb80ed |
hex | cf17c2d8f3f |
14231310012223 has 2 divisors, whose sum is σ = 14231310012224. Its totient is φ = 14231310012222.
The previous prime is 14231310012187. The next prime is 14231310012233. The reversal of 14231310012223 is 32221001313241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14231310012223 - 241 = 12032286756671 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14231310012233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115655006111 + 7115655006112.
It is an arithmetic number, because the mean of its divisors is an integer number (7115655006112).
Almost surely, 214231310012223 is an apocalyptic number.
14231310012223 is a deficient number, since it is larger than the sum of its proper divisors (1).
14231310012223 is an equidigital number, since it uses as much as digits as its factorization.
14231310012223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14231310012223 its reverse (32221001313241), we get a palindrome (46452311325464).
The spelling of 14231310012223 in words is "fourteen trillion, two hundred thirty-one billion, three hundred ten million, twelve thousand, two hundred twenty-three".
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