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142320144151 is a prime number
BaseRepresentation
bin1000010010001011110…
…0010000111100010111
3111121100112110102012001
42010202330100330113
54312432424103101
6145214142340131
713165553156653
oct2044274207427
9447315412161
10142320144151
11553a3013849
12236ba88a647
131056146b063
146c61821a63
153a7e771901
hex2122f10f17

142320144151 has 2 divisors, whose sum is σ = 142320144152. Its totient is φ = 142320144150.

The previous prime is 142320144103. The next prime is 142320144203. The reversal of 142320144151 is 151441023241.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 142320144151 - 213 = 142320135959 is a prime.

It is a super-2 number, since 2×1423201441512 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142320144251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71160072075 + 71160072076.

It is an arithmetic number, because the mean of its divisors is an integer number (71160072076).

Almost surely, 2142320144151 is an apocalyptic number.

142320144151 is a deficient number, since it is larger than the sum of its proper divisors (1).

142320144151 is an equidigital number, since it uses as much as digits as its factorization.

142320144151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 142320144151 its reverse (151441023241), we get a palindrome (293761167392).

The spelling of 142320144151 in words is "one hundred forty-two billion, three hundred twenty million, one hundred forty-four thousand, one hundred fifty-one".