14233331140139 has 2 divisors, whose sum is σ = 14233331140140. Its totient is φ = 14233331140138.

The previous prime is 14233331139977. The next prime is 14233331140141. The reversal of 14233331140139 is 93104113333241.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14233331140139 - 2²⁸ = 14233062704683 is a prime.

It is a super-3 number, since 3×14233331140139³ (a number of 40 digits) contains 333 as substring.

Together with 14233331140141, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14233331140739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116665570069 + 7116665570070.

It is an arithmetic number, because the mean of its divisors is an integer number (7116665570070).

Almost surely, 2^{14233331140139} is an apocalyptic number.

14233331140139 is a deficient number, since it is larger than the sum of its proper divisors (1).

14233331140139 is an equidigital number, since it uses as much as digits as its factorization.

14233331140139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 38.

The spelling of 14233331140139 in words is "fourteen trillion, two hundred thirty-three billion, three hundred thirty-one million, one hundred forty thousand, one hundred thirty-nine".