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14233344413 is a prime number
BaseRepresentation
bin11010100000101111…
…11001100110011101
31100201221112210221012
431100113321212131
5213122214010123
610312205545005
71012500300641
oct152027714635
940657483835
1014233344413
116044396362
122912875165
13145aa6c4b2
14990498c21
15584877378
hex3505f999d

14233344413 has 2 divisors, whose sum is σ = 14233344414. Its totient is φ = 14233344412.

The previous prime is 14233344407. The next prime is 14233344439. The reversal of 14233344413 is 31444333241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13928248324 + 305096089 = 118018^2 + 17467^2 .

It is an emirp because it is prime and its reverse (31444333241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14233344413 - 24 = 14233344397 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14233344413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14233304413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116672206 + 7116672207.

It is an arithmetic number, because the mean of its divisors is an integer number (7116672207).

Almost surely, 214233344413 is an apocalyptic number.

It is an amenable number.

14233344413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14233344413 is an equidigital number, since it uses as much as digits as its factorization.

14233344413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 32.

Adding to 14233344413 its reverse (31444333241), we get a palindrome (45677677654).

The spelling of 14233344413 in words is "fourteen billion, two hundred thirty-three million, three hundred forty-four thousand, four hundred thirteen".