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142341502021 is a prime number
BaseRepresentation
bin1000010010010000110…
…1101111010001000101
3111121102000122111200021
42010210031233101011
54313003411031041
6145220224215141
713166232542545
oct2044415572105
9447360574607
10142341502021
1155404081284
1223705a6a4b1
1310565a08554
146c645c1325
153a8158ecd1
hex212436f445

142341502021 has 2 divisors, whose sum is σ = 142341502022. Its totient is φ = 142341502020.

The previous prime is 142341501979. The next prime is 142341502031. The reversal of 142341502021 is 120205143241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96637048225 + 45704453796 = 310865^2 + 213786^2 .

It is an emirp because it is prime and its reverse (120205143241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142341502021 - 27 = 142341501893 is a prime.

It is a super-2 number, since 2×1423415020212 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142341502031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71170751010 + 71170751011.

It is an arithmetic number, because the mean of its divisors is an integer number (71170751011).

Almost surely, 2142341502021 is an apocalyptic number.

It is an amenable number.

142341502021 is a deficient number, since it is larger than the sum of its proper divisors (1).

142341502021 is an equidigital number, since it uses as much as digits as its factorization.

142341502021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 142341502021 its reverse (120205143241), we get a palindrome (262546645262).

The spelling of 142341502021 in words is "one hundred forty-two billion, three hundred forty-one million, five hundred two thousand, twenty-one".