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14234421133 is a prime number
BaseRepresentation
bin11010100000111000…
…00000011110001101
31100202000120111220201
431100130000132031
5213123002434013
610312245013501
71012512404032
oct152034003615
940660514821
1014234421133
116044a61309
1229130b4291
13145b0585ca
14990699389
155849db3dd
hex35070078d

14234421133 has 2 divisors, whose sum is σ = 14234421134. Its totient is φ = 14234421132.

The previous prime is 14234421109. The next prime is 14234421137. The reversal of 14234421133 is 33112443241.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13327086249 + 907334884 = 115443^2 + 30122^2 .

It is an emirp because it is prime and its reverse (33112443241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14234421133 - 25 = 14234421101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14234421137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7117210566 + 7117210567.

It is an arithmetic number, because the mean of its divisors is an integer number (7117210567).

Almost surely, 214234421133 is an apocalyptic number.

It is an amenable number.

14234421133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14234421133 is an equidigital number, since it uses as much as digits as its factorization.

14234421133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6912, while the sum is 28.

Adding to 14234421133 its reverse (33112443241), we get a palindrome (47346864374).

The spelling of 14234421133 in words is "fourteen billion, two hundred thirty-four million, four hundred twenty-one thousand, one hundred thirty-three".