Base | Representation |
---|---|
bin | 1000010010010110110… |
… | …0001101000001111111 |
3 | 111121110202020121202002 |
4 | 2010211230031001333 |
5 | 4313031230443341 |
6 | 145222511052515 |
7 | 13166653201313 |
oct | 2044554150177 |
9 | 447422217662 |
10 | 142366265471 |
11 | 55417055441 |
12 | 2371221113b |
13 | 1056ab98b91 |
14 | 6c679c9b43 |
15 | 3a8383229b |
hex | 2125b0d07f |
142366265471 has 2 divisors, whose sum is σ = 142366265472. Its totient is φ = 142366265470.
The previous prime is 142366265423. The next prime is 142366265497. The reversal of 142366265471 is 174562663241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142366265471 is a prime.
It is a super-3 number, since 3×1423662654713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142366265401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71183132735 + 71183132736.
It is an arithmetic number, because the mean of its divisors is an integer number (71183132736).
Almost surely, 2142366265471 is an apocalyptic number.
142366265471 is a deficient number, since it is larger than the sum of its proper divisors (1).
142366265471 is an equidigital number, since it uses as much as digits as its factorization.
142366265471 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1451520, while the sum is 47.
The spelling of 142366265471 in words is "one hundred forty-two billion, three hundred sixty-six million, two hundred sixty-five thousand, four hundred seventy-one".
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