Base | Representation |
---|---|
bin | 1100111100111000010010… |
… | …1101110111001100100101 |
3 | 1212102100001002120000211012 |
4 | 3033032010231313030211 |
5 | 3331302102024420232 |
6 | 50141441401552005 |
7 | 2666544355035533 |
oct | 317160455671445 |
9 | 55370032500735 |
10 | 14240043201317 |
11 | 45a019417169a |
12 | 171b9957a5605 |
13 | 7c3aa427038b |
14 | 373316765153 |
15 | 19a639a3e9b2 |
hex | cf384b77325 |
14240043201317 has 2 divisors, whose sum is σ = 14240043201318. Its totient is φ = 14240043201316.
The previous prime is 14240043201299. The next prime is 14240043201367. The reversal of 14240043201317 is 71310234004241.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11500773255841 + 2739269945476 = 3391279^2 + 1655074^2 .
It is a cyclic number.
It is not a de Polignac number, because 14240043201317 - 226 = 14239976092453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14240043201367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120021600658 + 7120021600659.
It is an arithmetic number, because the mean of its divisors is an integer number (7120021600659).
Almost surely, 214240043201317 is an apocalyptic number.
It is an amenable number.
14240043201317 is a deficient number, since it is larger than the sum of its proper divisors (1).
14240043201317 is an equidigital number, since it uses as much as digits as its factorization.
14240043201317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 14240043201317 its reverse (71310234004241), we get a palindrome (85550277205558).
The spelling of 14240043201317 in words is "fourteen trillion, two hundred forty billion, forty-three million, two hundred one thousand, three hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •