Base | Representation |
---|---|
bin | 100000011000011000011101… |
… | …101010101000011011111111 |
3 | 200200020112220110022202011102 |
4 | 200120120131222220123333 |
5 | 122131243332432100321 |
6 | 1222515350103043315 |
7 | 41666000323041461 |
oct | 4030303552503377 |
9 | 620215813282142 |
10 | 142413023315711 |
11 | 41417029a64265 |
12 | 13b8072144053b |
13 | 616064b759475 |
14 | 2724b81818131 |
15 | 116e7523bcc0b |
hex | 81861daa86ff |
142413023315711 has 2 divisors, whose sum is σ = 142413023315712. Its totient is φ = 142413023315710.
The previous prime is 142413023315677. The next prime is 142413023315737. The reversal of 142413023315711 is 117513320314241.
142413023315711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142413023315711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142413023312711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71206511657855 + 71206511657856.
It is an arithmetic number, because the mean of its divisors is an integer number (71206511657856).
Almost surely, 2142413023315711 is an apocalyptic number.
142413023315711 is a deficient number, since it is larger than the sum of its proper divisors (1).
142413023315711 is an equidigital number, since it uses as much as digits as its factorization.
142413023315711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 38.
Adding to 142413023315711 its reverse (117513320314241), we get a palindrome (259926343629952).
The spelling of 142413023315711 in words is "one hundred forty-two trillion, four hundred thirteen billion, twenty-three million, three hundred fifteen thousand, seven hundred eleven".
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