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142421601255503 is a prime number
BaseRepresentation
bin100000011000100000011100…
…111100111000000001001111
3200200021101001021020020102012
4200120200130330320001033
5122131413414410134003
61222523325210051435
741666423022241343
oct4030403474700117
9620241037206365
10142421601255503
114141a730a923a9
1213b82316119b7b
1361613b794309b
142725356b65623
15116eaa54c98d8
hex81881cf3804f

142421601255503 has 2 divisors, whose sum is σ = 142421601255504. Its totient is φ = 142421601255502.

The previous prime is 142421601255467. The next prime is 142421601255589. The reversal of 142421601255503 is 305552106124241.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (305552106124241) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 142421601255503 - 28 = 142421601255247 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142421601255403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71210800627751 + 71210800627752.

It is an arithmetic number, because the mean of its divisors is an integer number (71210800627752).

Almost surely, 2142421601255503 is an apocalyptic number.

142421601255503 is a deficient number, since it is larger than the sum of its proper divisors (1).

142421601255503 is an equidigital number, since it uses as much as digits as its factorization.

142421601255503 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288000, while the sum is 41.

Adding to 142421601255503 its reverse (305552106124241), we get a palindrome (447973707379744).

The spelling of 142421601255503 in words is "one hundred forty-two trillion, four hundred twenty-one billion, six hundred one million, two hundred fifty-five thousand, five hundred three".