142423117 has 2 divisors, whose sum is σ = 142423118. Its totient is φ = 142423116.

The previous prime is 142423097. The next prime is 142423121. The reversal of 142423117 is 711324241.

142423117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123010281 + 19412836 = 11091^2 + 4406^2 .

It is an emirp because it is prime and its reverse (711324241) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-142423117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 142423091 and 142423100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142423417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71211558 + 71211559.

It is an arithmetic number, because the mean of its divisors is an integer number (71211559).

Almost surely, 2^142423117 is an apocalyptic number.

It is an amenable number.

142423117 is a deficient number, since it is larger than the sum of its proper divisors (1).

142423117 is an equidigital number, since it uses as much as digits as its factorization.

142423117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1344, while the sum is 25.

The square root of 142423117 is about 11934.1156773345. The cubic root of 142423117 is about 522.2280104199.

Adding to 142423117 its reverse (711324241), we get a palindrome (853747358).

The spelling of 142423117 in words is "one hundred forty-two million, four hundred twenty-three thousand, one hundred seventeen".