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142432355425501 is a prime number
BaseRepresentation
bin100000011000101010011101…
…111100110001110011011101
3200200022101210202002200021201
4200120222131330301303131
5122132102430442104001
61222532304253155501
742000253355210551
oct4030523574616335
9620271722080251
10142432355425501
114142424a4854a9
1213b8441778bb91
13616240c95809b
142725a97123861
15116eed46aa501
hex818a9df31cdd

142432355425501 has 2 divisors, whose sum is σ = 142432355425502. Its totient is φ = 142432355425500.

The previous prime is 142432355425499. The next prime is 142432355425631. The reversal of 142432355425501 is 105524553234241.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87041921299876 + 55390434125625 = 9329626^2 + 7442475^2 .

It is a cyclic number.

It is not a de Polignac number, because 142432355425501 - 21 = 142432355425499 is a prime.

It is a super-2 number, since 2×1424323554255012 (a number of 29 digits) contains 22 as substring.

Together with 142432355425499, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (142432355425001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71216177712750 + 71216177712751.

It is an arithmetic number, because the mean of its divisors is an integer number (71216177712751).

Almost surely, 2142432355425501 is an apocalyptic number.

It is an amenable number.

142432355425501 is a deficient number, since it is larger than the sum of its proper divisors (1).

142432355425501 is an equidigital number, since it uses as much as digits as its factorization.

142432355425501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880000, while the sum is 46.

The spelling of 142432355425501 in words is "one hundred forty-two trillion, four hundred thirty-two billion, three hundred fifty-five million, four hundred twenty-five thousand, five hundred one".